C++函数模板偏特化问题较为美观的一种解决方案

template <typename T, typename std::enable_if_t<std::is_integral_v<T>, int> = 0>
void foo(T x) {
    std::cout << "is integral\n";
}

template <typename T, typename std::enable_if_t<std::is_floating_point_v<T>, int> = 0>
void foo(T x) {
    std::cout << "is floating point\n";
}