C++函数模板偏特化问题较为美观的一种解决方案

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template <typename T, typename std::enable_if_t<std::is_integral_v<T>, int> = 0>
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void foo(T x) {
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    std::cout << "is integral\n";
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}
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template <typename T, typename std::enable_if_t<std::is_floating_point_v<T>, int> = 0>
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void foo(T x) {
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    std::cout << "is floating point\n";
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}